x^(1/2)+x^(1/4)=20

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Solution for x^(1/2)+x^(1/4)=20 equation: 


D( x )

x < 0

x < 0

x in <0:+oo)

x^(1/2)+x^(1/4) = 20 // - 20

x^(1/2)+x^(1/4)-20 = 0

t_1 = x^(1/4)

1*t_1^2+1*t_1^1-20 = 0

t_1^2+t_1-20 = 0

DELTA = 1^2-(-20*1*4)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)-1)/(1*2) or t_1 = (-81^(1/2)-1)/(1*2)

t_1 = 4 or t_1 = -5

t_1 = -5

x^(1/4)+5 = 0

1*x^(1/4) = -5 // : 1

x^(1/4) = -5

( -5 < 0 i 1/4 in (0:1) ) => x naleu017Cy do O

t_1 = 4

x^(1/4)-4 = 0

1*x^(1/4) = 4 // : 1

x^(1/4) = 4

x^(1/4) = 4 // ^ 4

x = 256

x = 256

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